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Do anyone have any ideas on how to find the total flow rate in a pump parallel piping system?
The total flow rate is the sum of the flow rates of each pump
Theoretically it’s the sum, but in practice it can’t be achieved due to pipeline limitations
This post was last edited by tjuliusuan on 2016-9-6 at 10:28. There is a problem with this question; it should be calculated using K=0, and the result is 118 m3. H=K+GQ2, with Q1/Q2 being used in this calculation
After parallel connection, the pressure drop is equal to the pump head, and the pressure drops in the parallel pipelines are identical. Based on these two principles, the value 115 is obtained. Does anyone have this answer?
At first glance, this problem doesn’t involve changes in the standard pump curve equations; instead, it requires finding the pipeline equation. The amount of calculation involved is likely to be significant, so I gave up on it. . . .
K=0 seems a bit arbitrary; the definition of K in the pipeline equation cannot be 0, but rather it should be the sum of pressure energy and potential energy
K can be calculated based on the initial flow rate and head pressure, and B can also be calculated using the resistance formula. I’m not sure what to do next
Both K and G are unknown variables; only one of the flow rate or head can be determined. G can be calculated only when K is equal to 0. Even if it is assumed that this is a special case and the flow rate turns out to be 118, the method used may not be correct, but the result should be correct—the answer is unique. What is special is actually universal
No, wasn’t it the resistance at the beginning? Isn’t that just b? Then k can be calculated based on the head pressure. You’re really smart