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The equipment supports bear the weight; for example, if a piece of equipment has 4 supports, then each support should bear 1/4 of the total weight of the equipment?

2016-12-05View Original

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The equipment supports the weight of the device; for example, if a device has 4 supports, then each support should bear 1/4 of the total weight of the device. Is this calculation reasonable? For example, in the case of a 25-cubic-meter reactor with a net weight of 12 tons, the total weight after it is in operation is approximately 32 tons; therefore, each support should be designed to handle a load of 32/4, which is 8 tons. Is this calculation reasonable?
Reply #22016-12-05
The theory suggests an even distribution, but in reality, due to manufacturing errors and uneven settlement of the foundation, it is not possible to ensure that all legs are subjected to force at the same time
Reply #32016-12-05
You can multiply it by an imbalance coefficient
Reply #42016-12-06
This calculation is reasonable; for safety reasons, it is still necessary to multiply by an imbalance factor.
Reply #52016-12-06
It can’t be like this. Because in reality, it is not possible to have all 4 supports bear the load simultaneously; at most, 3 supports can be considered
Reply #62016-12-06
The standard appendices include the selection calculation methods; it is necessary to multiply by the unbalance factor.
Reply #72016-12-06
According to JB/T4712, it is understood in this way; one can refer to the calculation examples provided at the end of the standard
Reply #82016-12-06
It seems there’s a coefficient of 0.83
Reply #92016-12-07
Agree with the views of those above; it is also necessary to multiply by the imbalance factor

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