Calculation of the buoyancy of buoys
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1. It is known that there is a stainless steel pipe inside the oil tank, with a length of 15 meters, a diameter of 273 mm, and a thickness of 5 mm.2. The medium inside the tank is bio-oil, with a density of 880 kg/m3.
3. It is required to create two cylindrical, hollow floats that can float on the surface of the oil and be used to pull up the steel pipe at the bottom. The diameter of these floats is 500 mm; it is necessary to calculate their length It would be best to have a detailed calculation process. Thank you!
This post was last edited by lupg on 2021-12-4 at 22:27. 1. Conditions not specified: the thickness of the buoy is 5 mm, it is tubular in shape, and it is submerged in the liquid to 50% and 90% of its height respectively. 2. The calculation is based on Archimedes’ principle; the two lengths of the buoy correspond to the different percentages of submersion. Using these values, it is possible to lift the stainless steel pipe at the bottom of the tank. To raise it above the liquid surface, the buoy’s submersion level needs to increase by about 6%. 3. The calculation involves simple relationships related to volume, area, and weight; the key is to understand Archimedes’ principle.