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2011年度の専門科目、初日の午前中の28番問題について質問です

2016-05-29View Original

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28、水の流速が590m/sの熱交換器で、水の入口温度は20℃、取り出される熱量が3.5×104kJ/sであり、水の比熱容量は4.1868 kJ/(kg•℃)である。熱損失は無視するとき、水の出口温度(℃)は以下のうちどれか? A、40 B、35 C、45 D、34 この水の流量、なんだかおかしい気がするけど?
Reply #22016-05-29
流量の単位がm/sなんて、明らかに問題だ
Reply #32016-05-30
Dの質量流量はkg/sでなければならない; 590*4.1868(T-20)=35000、T=34℃

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