注化試験 物理化学 一問
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1. 刚性密封容器に1molの単原子理想気体が入っており、25℃で系がある過程を経た後、△S=1.0J·Kとなった。このとき系の△Uはいくら変化したか？詳しい解説をお願いします
ds＝＆Q/T、Q＝T*△S＝298*1＝298。剛性容器のW＝0。△U＝Q+W＝Q＝298
ありがとう、でも答えは1000だったので迷ってしまいました
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