How much lime is needed to neutralize one ton of 93% sulfuric acid?
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How much lime is needed to neutralize one ton of 93% sulfuric acid?
This post was last edited by qugd on 2019-9-2 at 10:16. For such problems, knowledge of chemistry acquired in high school is sufficient. It’s really concerning that the person who posted this didn’t even finish high school; they had to start working due to life circumstances, yet still had to take on tasks that require chemical knowledge. However, it should be noted that lime is best ground before being neutralized, as this improves efficiency.
I really didn’t finish high school – how should that be counted?
This falls within the scope of junior high school chemistry. How do you guide your child to do this?
We are a manufacturer specializing in lime production in the Henan region. If you need it, feel free to contact me; I’m not sure how to calculate the cost either
This is clearly a practical application-based calculation; it has nothing to do with junior high school level knowledge. Lime also has specific criteria to consider – incomplete burning is not the same as complete burning. Using junior high school-level calculations will definitely yield an underestimation. Factors such as particle size and heat transfer also need to be taken into account. Additionally, the reaction between concentrated sulfuric acid and lime is not simple at all. It’s possible to estimate roughly.
Also, only basic junior high school knowledge is needed to carry out such calculations; in practice, lime is rarely used to neutralize 93 acid. Isn’t 93 acid a type of resource?