Please, I’ve been thinking about it for a day or two without figuring it out
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I’m new to the fertilizer chemicals industry and am not sure: for 300,000 tons of ammonium phosphate fertilizer, how much phosphoric acid with 100% P2O5 is required? And why does phosphorus have to be converted into P2O5? It’s confusing; can’t it just be counted as phosphorus itself? Please, big brother, help me figure this out; detailed calculation formulas would be great
Monoammonium phosphate is a phosphorus-containing fertilizer whose main components are ammonia and phosphoric acid. Due to the different masses and concentrations of phosphoric acid, it is necessary to convert it into the mass of phosphorus dioxide (P2O5), as phosphorus dioxide is a widely used unit for phosphorus fertilizers in agricultural production. The conversion formula is as follows: Mass of P2O5 = Mass of phosphoric acid × (Molecular weight of P2O5 / Molecular weight of H3PO4). The molecular weight of P2O5 is 142 grams per mole, while the molecular weight of H3PO4 is 98 grams per mole. Assume you need to produce 300,000 tons of monoammonium phosphate, with a composition containing 30% P2O5. The amount of 100% phosphoric acid required can be calculated as follows: 30,000,000 kilograms × 0.3 = 9,000,000 kilograms of P2O5. So, how much 100% P2O5 phosphoric acid is needed? Using the conversion formula above for calculation: 9,000,000 kilograms / (142 grams/mole ÷ 98 grams/mole) = 6,233,766.23 kilograms. Therefore, 6,233,766.23 kilograms of 100% P2O5 phosphoric acid is required. I hope this clears up your doubts. .