Calculation of enthalpy value after heating normal-temperature air
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How to calculate the enthalpy of 1 kg of saturated air at 25°C after it is heated to 100°C? With a humidity of 20 g/kg of dry air, 1 kg of saturated air contains 0.02/1.02 kg of water and 1/1.02 kg of dry air. The enthalpy of saturated air at 25°C is 75.78; therefore, the total enthalpy is calculated as follows: 75.78 [enthalpy of saturated air at 25°C] × 1 [mass of saturated air] + 1 [specific heat capacity of dry air] × 1/1.02 [mass of dry air] × (100–25) [temperature difference] + 4.2 [specific heat capacity of water] × 0.02/1.02 [mass of water] × (100–25) [temperature difference] + 0.02/1.02 [mass of water] × 2260 [vaporization latent heat of water at 100°C]. The result is 75.78 + 73.53 + 6.176 + 44.314 = 199.8 KJ. Please help me check if there are any mistakes in this calculation
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