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1. The center height for a bend with a 1.5x factor is equal to the diameter multiplied by 1.524; in other words, it’s the diameter multiplied by that factor. The decimal part of the resulting value is rounded to the nearest whole number. For example, if the diameter is 200, then the center height is 200*1.524 = 304.8, so the result is 305. Another example: if the diameter is 100, then the center height is 100*1.524 = 152.4, so the result is 152. (This algorithm is suitable for elbow radii of DN100 and above, enabling quick calculations.) 2. The projected height = center height + radius of the elbow; for example, for an elbow with a diameter of 219 and a 1.5 times factor, the projected height = 305 + 219/2 = 305 + 109.5 = 414.5. 3. The length of the outer arc = (center height + radius) * 3.14 * 2 / 360 * degrees; in other words, it is (height from center) * 3.14 * 2 / 360 * degrees. From this, it can be calculated that the length of the outer arc for a 90-degree elbow is equal to height from center * 3.14 / 2. 4. The length of the inner arc = (center height – radius) * 3.14 * 2 / 360 * degrees. 5. The cutting length for a elbow = center height of the elbow * 3.14/2 * outer diameter of the elbow / diameter of the pipe + (wall thickness of the pipe * 3) + machining allowance. For example, when using a pipe with dimensions of 180*8 to manufacture an elbow with a diameter of 273, the cutting length can be calculated using the formula above: Cutting length = 381*1.57*273/180 + 24 = 931.22 mm + machining allowance. The calculation method for multiple bends is the same as that for elbows.
90° elbow center length (mm) = R * 1.57 (bending radius in mm) 2) Weight of steel plate (T) = 7.85 * length * width * thickness (length, width, thickness in meters) 3) Material required for 90° elbow (M) = diameter * 2.5 * number required + radius
Teaching on how to lay out insulation for iron sheet shrimp-shaped elbows; construction of insulation using iron sheet shrimp-shaped elbows. During the process of installing iron sheet insulation, components such as elbows and tees with varying diameters come up, and it is necessary to determine how to cover these elbows and curved pipes with a layer of metal sheet for insulation purposes.