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1. Quantities of rust removal, oil brushing, and anti-corrosion work (1) The calculation formula for the surface area of equipment cylinders and pipelines is S=π×D×L (π--pi, D--diameter of equipment or pipes, L--length of equipment or pipes) Φ219mm pipe is 26m long, calculate its outer surface area S=0.219* 3.14 * 26S=17.87916m2; (2) Valve surface area calculation formula S=π×D×2.5 D×K×N (D--diameter, K--coefficient, K=1.05, N--number of valves) Φ325mm valve, quantity 8, calculate its outer surface area S=3.14 * 0.325 * 2.5 * 0.325 * 1.05 * 8S=6.9649125m2; (3) Elbow surface area calculation formula S=π×D×1.5 D× 2π× N/B (D--diameter, K--coefficient, K=1.05, N--number of elbows, 900 elbow B=4, 450 elbow B=8) 900, 12 Φ108mm elbows, 450, 16 Φ159mm elbows, calculate the outer surface area S=3.14 * 0.108 * 1.5 * 0.108 * 2 * 3.14 * 12/4=1.0350213696mS=3.14 * 0.159 * 1.5 * 0.159 * 2 * 3.14 * 16/8=1.4955632856m2;S=1.03+1.49=2.53 (4) Flange surface area calculation formula S=π×D×1.5 D×K×N (D—diameter, K—coefficient, K=1.05, N number of flanges) There are 4 Φ426mm flanges, and their outer surface area is calculated as S=3.14 * 0.426 * 1.5 * 0.426 * 1.05 * 4=3.589958232m2; (5) Calculation formula for equipment head surface area S=π×r2×1.5×N (r—radius of equipment, number of N heads) 2 Φ1200mm heads, calculate their outer surface area S=3.14 * 0.6 * 0.6 * 1.5 * 2=3.3912m2; 2. Insulation engineering (1) Calculation formula of equipment cylinder or pipe insulation, moisture-proof and protective layer V=π×(D+1.033δ)×1.033δ×L S = π * (0.529+1.033 * 0.1) * 1.033 * 0.1 * 35= 7.178293241m³ S=3.14 * (0.529+2.1 * 0.1+0.0082) * 35= 82.11728m² (2) Valve insulation, moisture-proof and protective layer calculation formula V=π×(D+1.033δ)×2.5D×1.033δ×1.05×N S=π×(D+2.1δ)×2.5D×1.05×N (D—diameter, 1.033, 2.1—adjustment coefficient, δ insulation layer thickness, N—number of valves) Φ89mm valve, quantity 6, insulation layer thickness 60mm, protective layer made of iron sheet, calculate the volume of the insulation layer and the area of the protective layer V=3.14 * (0.089+1.033 * 0.06) * 2.5 * 0.089 * 1.033 * 0.06 * 1.05 * 6=0.04 m3; S=3.14 * (0.089+2.1 * 0.06) * 2.5 * 0.089 * 1.05 * 6=0.95 m2; (3) Flange insulation, moisture-proof and protective layer calculation formula V=π×(D+1.033δ)×1.5D×1.033δ×1.05×NS=π×(D+2.1δ)×1.5D×1.05×N (D—diameter, 1.033, 2.1—adjustment coefficient, δ insulation layer thickness, N—number of flanges) Φ377mm flange, quantity 4, insulation layer thickness 80mm, protective layer adopts color steel plate, calculate the volume of insulation layer and area of protective layer V=3.14 * (0.377+1.033 * 0.08) * 1.5 * 0.377 * 1.033 * 0.08 * 1.05 * 4= 0.2832824515719744 m3; S=3.14 * (0.377+2.1 * 0.08) * 1.5 * 0.377 * 1.05 * 4= 4.06450863m2; 4) Elbow insulation, moisture-proof and protective layer calculation formula V=π×(D+1.033δ)×1.5D×2π×1.033δ×N/BS=π×(D+2.1δ)×1.5D×2π×N/B (D—diameter, 1.033, 2.1—adjustment coefficient, δ insulation layer thickness, N—number of elbows, 900 elbow B=4, 450 elbow B=8) Φ273mm elbow, 900, quantity 6, insulation layer thickness 120mm, moisture-proof layer using glass fiber cloth, protective layer using color steel plate, calculate the volume of the insulation layer and the area of the moisture-proof layer and protective layer V=3.14 * (0.273+1.033 * 0.12) * 1.5 * 0.273 * 2 * 3.14 * 1.033 * 0.12 * 6/4= 0.59602266013320576 m3; S=3.14 * (0.273+2.1 * 0.12) * 1.5 * 0.273 * 2 * 3.14 * 6/4= 6.359072265m2; (5) Calculation formula for equipment head insulation, moisture-proof and protective layer V=^2×π×1.033δ×1.5×N (N—number of heads) S=2×π×1.5×N (D-diameter, 1.033, 2.1-adjustment coefficient, δ insulation layer thickness, N--number of heads) 2 Φ1800mm heads, insulation layer thickness 90mm, moisture-proof layer using plastic cloth, protective layer using color steel plate, calculate the volume of the insulation layer and the area of the moisture-proof layer and protective layer V=[(1.8+1.033 * 0.09)/2】^2 * 3.14 * 1.033 * 0.09 * 1.5 * 2=0.78 S=[（1.8+2.1 * 0.09)/2】^2; * 3.14 * 1.5 * 2=9.32 (6) The calculation formula for the insulation, moisture-proof and protective layer of the vault tank is V=2πr×(h+1.033δ)×1.033δ S=2πr×(h+2.1δ) (r is the radius of the spherical part of the vault, h is the arch height of the vault, 1.033, 2.1 - adjustment coefficient) The radius of the upper vault of an oil tank is 22m, the arch height is 1.8m, the thickness of the insulation layer is 90mm, the wire mesh is used as the protective layer, and the outer sheath is made of profiled steel plates. Calculate the volume of the insulation layer and the area of the wire mesh and outer sheath V=2 * 3.14 * 22 * (1.8+1.033 * 0.09) * 1.033 * 0.09=24.31 m3; S=2 * 3.14 * 22 * (1.8+2.1 * 0.09)=274.80 m2;