Calculate the water flow rate for mixed heat exchange
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When a substance is placed in water and the two do not mix with each other, the temperature is reduced from 900 degrees to 40 degrees. The temperature of the water increases from 25 degrees to 40 degrees. Given that the specific heat capacity of this substance is 0.3 kcal/kg, and the daily usage amount is 4000 tons, how much water is required per day? I’ve spent a long time trying to understand the enthalpy of vaporization associated with the increase in temperature of the water from 25 degrees to 40 degrees, but I still haven’t figured it out.
This is too simple; there are several algorithms. Give 2: Q=enthalpy of steam at 40°C minus enthalpy of water at 20°C; Q=4.187×(40–20)+latent heat of vaporization at 40°C......