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Seeking help with heat exchange calculations; a detailed explanation is needed.

2019-02-23View Original

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Given that water flows through a heat exchanger at 2 L/S with an input temperature of 52°C, how much energy input is required to achieve an output temperature of 60°C? Thank you in advance!
Reply #22019-02-23
Something similar... In fact, many people have already calculated it... Including myself, I’ve written down the formula several times: Q = M*Cp*(T2-T1). Here, M = 2L/S (please convert the units by yourself), Cp is the specific heat capacity (please look it up by yourself), T2 = 60 and T1 = 52. With these values, the value of Q can be calculated...
Reply #32019-02-23
Haha, thanks. I found this formula after work, but the condition is that there are no phase transitions occurring within the system; it’s an isolated system with no exchange of matter or energy with the outside world. In other words, excluding factors such as heat transfer efficiency, it refers solely to the net energy input. This question was given by a development company; there is no standard answer, only critical thinking is required. So simple that it makes one doubt their motives.
Reply #42019-02-25
Water does not undergo any phase changes at temperatures between 52 and 60 degrees... You’re worrying too much~*
Reply #52019-02-25
Haha, if it’s a system for hot water inlet and outlet, how many processes are there in between?

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