1.1 A total of 2 disinfection exhaust gas condensers are to be installed in the comprehensive fermentation workshop. Each condenser is capable of cooling 10 T/h of fermentation exhaust gas; the inlet temperature of the gas to the condensers is around 130°C, with an inlet pressure of 0.10–0.13 MPa. Circulating water is provided at a pressure of 0.3–0.4 MPa and at a temperature of 32°C (in summer), with a wet bulb temperature of 2
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Teachers, please take a look. There’s an error in the calculation method. I would appreciate it if you could give me some advice. Thank you!
Condensation is primarily the cooling of sterilization steam, as it changes from a gaseous state to a liquid state and its temperature drops to room temperature. It is necessary to know the maximum amount of steam used during sterilization. Normal fermentation off-gas is at room temperature.
The heat transfer amount was calculated incorrectly; it seems you calculated the weight instead. It should be calculated using specific enthalpy. I get it now; treat it as if it’s all water. Q=10x(2720-167.54)X1000 KJ. The area should be at least three digits, possibly approaching four digits.
Can the heat exchange area approach four digits?
The heat is more than ten times greater, right? !
This post was last edited by wanlirn on 2021-8-16 at 11:19. You’ve mistaken steam for water, buddy; latent heat should be used, along with the supercooled portion, and then it can be calculated as water. I did a quick calculation; the heat exchange rate in the steam condensation stage is around 6,000 KW or so. I also got the unit for specific heat wrong – it seems like I still haven’t mastered this yet
Gas heat exchange is calculated using the enthalpy difference