Volume of ethanol and water after mixing
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For a mixture of 1000 L, if the volume percentage of ethanol is 60%, then the volume of ethanol should be 1000 L x 60% = 600 L. The corresponding volume of water would then be 1000 L x 40% = 400 L. However, when 600 L of ethanol and 400 L of water are mixed together, their total volume decreases. To obtain a solution with 60% ethanol, more water must be added so that the total volume returns to 1000 L. In this case, the volume percentage of water is no longer 40%. Why is this?
It’s the reaction of ethanol with water; it took too long, I forgot what it’s called… ethanol hydrate? ? ? ?
Why go to the trouble of using volume concentration to express it? The volume changes after mixing, and it is dependent on temperature. Using mass or molar concentration will eliminate such problems! Imagine how difficult it would be to mix soybeans and mung beans to achieve a certain volume concentration!
I just suddenly thought of this question and wanted to find an answer: lol