Electric power required to evaporate water
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To build a atmospheric pressure evaporator that can evaporate 2000 kg of water from 5000 kg of water at 20 degrees Celsius within 8 hours, what electrical power is required if electric heating elements are used for heating?
I calculated that it will take around 269 KW. If any of you know how to do this calculation, please help me figure it out
Heat required to raise 5000 kg of water by 80°C: 5000×4.2×80=1680000 KJ； Heat required to evaporate 2000 kg of water at 100°C: 2257.2×2000=4514400 KJ ； The sum of the two is 619400 KJ ； Electrical power: 619400/8/3600=215.1KW; electrical heating efficiency 90% ； Heat loss for cooling: 0.1; required power: 215.1/0.9/(1-0.1) = 265 KW
What is the value of 2257.2 on the 3rd floor?