Calculation of natural water evaporation from open containers
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As the title says. In an open container, evaporation occurs naturally at a certain temperature. How is the amount of evaporation calculated?
Things related to the atmosphere, wind speed, temperature, and humidity can be queried directly with the meteorological office. For example, what the original poster mentioned is a typical meteorological parameter known as \"annual evaporation rate\"; in the saline-alkali lands of Lop Nur in Xinjiang, the annual rainfall is less than 40 mm, while the annual evaporation rate is around 4,000 mm. If one really wants to do the calculations, it involves empirical formulas, those given in the \"Handbook of Environmental Statistics\": you just need to replace the medium mentioned there with water. There are also example problems for reference, but to be honest, the accuracy of such calculations isn’t as high as that of the annual statistical data provided by weather stations. .
This value is very small; you can refer to the scaling section in chemical process flow studies for consideration
Thank you very much. Could you post the cover of this book?
It’s right in the jar. . . http://bbs.hcbbs.com/thread-870563-1-1.html
The 10,350.8g shown in the screenshot above is not equal to 1.035kg; nevertheless, thanks to the original poster for the information