I have a question regarding the heat release during steam liquefaction
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I was forced to work on this manufacturing process; almost all the previous materials were discarded :(. I would like to ask: in a heater where steam is used as the heat source and it turns back into water at a constant temperature, how should the heat released be calculated?
First calculate the latent heat, then calculate the heat generated by the temperature difference； Or calculate it directly using the enthalpy difference
Simply find the enthalpy values of water vapor and water at that temperature; the difference between them represents the theoretical heat release amount. Is that correct? For example, at 200°C, the specific enthalpy of steam is 667.1 Kcal/kg, while that of water is 203.6 Kcal/kg. If the heat carrier in the heat exchanger only undergoes a phase change without any changes in temperature or pressure, then the heat release per kilogram of steam would be 667.1 – 203.6 = 463.5 Kcal, right?
It is the latent heat of steam at a certain temperature and pressure.
Oh, so it means the latent heat of vaporization of water at a certain temperature and pressure is this amount? And conversely, the same amount of heat is released when steam liquefies, right?
Oh, so it means the latent heat of vaporization of water at a certain temperature and pressure is this amount? And conversely, the same amount of heat is released when steam liquefies, right?
1. The latent heat of vaporization at a certain pressure can be found, but this is possible only if the dry steam condenses into water, that is, when the steam dryness decreases from 1 to 0.2. In practical applications, it is important to ensure that the steam fully condenses; otherwise, the latent heat cannot be utilized fully. Appropriate superheat and subcooling can be applied during the operating condition design
What is released when the temperature remains unchanged is the latent heat at that temperature.