Can ammonia be liquefied by expansion?
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As the title suggests, can gaseous ammonia at 40°C and 1.6 MPa be liquefied through adiabatic expansion? If possible, what is the temperature in the expanded state? What’s the pressure?
Isn’t expansion a form of vaporization? How can it lead to liquefaction? Read more on the principles of chemical engineering. Asking silly questions; even if I told you, you wouldn’t understand anyway
Those without education, stop making jokes, haha! Let’s put it this way: at 40°C and 1.6 MPa, what is the temperature after adiabatic expansion to 0.3 MPa? Thank you!
Ask any theoretical question – it’s very difficult to provide a clear answer for them. http://www.doc88.com/p-9032693969216.html provides data on the saturated vapor pressure of ammonia; the 0.3 Mpa you mentioned is likely gauge pressure, so the actual value is 0.4 Mpa, corresponding to a temperature of 0°C. Is this property the data you need? Deeper theoretical research is pointless; solving practical problems is what matters
Thank you very much. I’m interested in knowing the temperature change when ammonia at 1.6 MPa expands to 0.3 MPa; it’s not necessary for it to reach saturation exactly! Thank you! !
This post was last edited by Luo Peng on 2017-11-2 09:03
The last edit to this post was made by Luo Peng on 2017-11-2 at 09:17; it might look like this~~~~~Saturated gas at 40°C, and after pressure is reduced, part of it liquefies
This is exactly what I had in mind; thank you so much! ! ! !
As I thought, it’s 1.46 MPa; after depressurizing and expanding to 0.3 MPa at 40°C, the temperature drops to -1.54°C, right? Is 9.2% of it the liquid phase? Is this simulated by software?