What is the state of saturated water vapor mixed with unsaturated water?

First, explain what this unsaturated water vapor is – did you add N2 to the steam?

At 0.3 MPa, the temperature of saturated steam is 133.5°C. When saturated water vapor is mixed with hot water at 120°C, a two-phase flow is formed; the temperature remains at 133.5°C, and the gas phase fraction is 0.4128

Hello, these are two types of waste heat from a chemical manufacturing plant: one is saturated steam, and the other is hot water. We are now considering mixing these two streams together and feeding them into a waste heat recovery system to generate electricity

The calculation is done in two steps: 1. For 6 t/h of saturated steam at 0.3 pressure, if all of it were converted to saturated water, the latent heat of water is 500 kcal/kg; therefore, the heat released would be 500×6 = 3000 kcal. 2. For 8 t/h of unsaturated water at 120°C, to convert it to saturated water at 133°C, the heat required is 8×13 = 104 kcal. Comparing these values, it is clear that the amount of heat released when saturated steam is converted to saturated water is much higher than the heat required to convert unsaturated water to saturated water. Well, obviously in the end all the water is still saturated water, but there is still some saturated steam. Doing a simple conversion, 104/500 = 0.21 tons; therefore, there are 8.2 tons of water and 5.8 tons of gas. The gas phase fraction is 5.8/14=41%. It’s roughly the same as the calculation above. Because I have simplified the calculation of latent heat and the specific heat of warm water by assuming values of 500 and 1 respectively. Perform detailed calculations; you need to refer to tables for the specific computations.

How does this 0.21 come about? Could you please indicate the formula, dear?

0.21t is the amount of steam required to convert 8 tons of unsaturated water into saturated water.