Calculations of relevant flow rates for several heating and cooling processes in the reaction vessel
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The raw material is a liquid fragrance, with a density of 800–1000 kg/m3 and a viscosity of 50–500. Currently, there are reactors of 1200L, 1300L, 2400L, and 3500L capacity ； When 0.3 MPa of steam is used, the raw material (at atmospheric pressure) is raised from 20°C to 100°C within 40 minutes, completing the heating process ； When using 7℃ chilled water, the raw material is cooled from 20℃ to 10℃ within 60 minutes (at atmospheric pressure), thus completing the cooling process ； When using 7℃ chilled water, the raw material is cooled from 80℃ to 10℃ within 60 minutes (at atmospheric pressure), thus completing the cooling process ； When cooling with chilled water at -25°C, the raw material is cooled from 20°C to -20°C within 70 minutes (at atmospheric pressure), achieving the cooling process; the temperature difference of the chilled water is 5℃ ； In these processes, how are the chilled water flow rate and steam flow rate calculated? (Just graduated students with a non-related major; they have only a basic understanding of heat transfer calculations, and still need to consult their seniors for more detailed information.) ）
The ingredients are mostly fragrances with water-soluble substances as solvents; for example, using the specific heat of water (4.178 kj/kg·℃), it is still necessary to determine which formula should be used for the calculations.
Q=m*Cp*ΔΤ; the heat load on the cold flow side can be calculated using the mass flow rate of the liquid fragrance in KG/h, its specific heat, and the temperature rise (temperature difference). According to the heat balance, the heat load on the hot side equals the heat load on the cold side; given the heat load on the hot side and the latent heat of vaporization of 0.3 MPa steam (which can be found in relevant sources), the required steam flow rate can be calculated. Similarly, the chilled water consumption for several other processes can be calculated, provided that the specific heat of chilled water is known.
:Lol, thank you so much; I understand it right away.