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Dear colleagues in the chemical industry, I’m new to this field and have a question. There is an evaporation tank with a capacity of 1500 L in the workshop, used for evaporating propylene and extracting solutions. Propylene is added to the tank in an amount equal to half of its capacity. How should the evaporation volume be calculated? Is it necessary to install a gas-liquid separator at the top of the evaporation tank? What size gas-liquid separator should be used? Thank you!
This question is not suitable for those new to the chemical industry
S=Q/KΔT; once the area, heat transfer coefficient, and temperature difference are known, Q can be calculated. By then dividing Q by the latent heat of vaporization, the amount of evaporation can be estimated. A gas-liquid separator is generally necessary, and the calculations related to such a separator are specified in the technical specifications for process system engineering
This depends on the amount of external heat in KW, as well as the heat of vaporization at the initial temperature; by dividing heat by heat of vaporization, it is possible to determine the theoretical amount of vaporization at the initial temperature
What is the standard number applicable to this calculation?
Can you give me the data directly? I’m not majoring in chemical engineering
Heated with steam; the stainless steel reactor has a jacket, but it’s sufficient to control the temperature at around fifty to sixty degrees
What are the inlet temperature/flow rate and outlet temperature/flow rate of the vapor? Or how much energy can the front end provide?
https://bbs.hcbbs.com/thread-2789717-1-1.html Custom gas-liquid separator process calculation table
If the temperature remains constant and the liquid level is stable, then the amount of cold liquid flowing in per hour equals its evaporation rate; if the temperature changes, the evaporation rate also changes