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In a certain scenario, only the specific gravity of the material is known; the material is in suspension. How can one calculate the weight of the solids in such a suspension{:9006:}?
To determine the weight of the solids in a suspension using specific gravity, follow these steps: 1. **Identify the relevant data**: - Measure the total volume $V$ of the suspension (the unit can be cubic meters or liters). - Determine the total mass $m$ of the suspension (in kilograms). - The specific gravity $SG$ of a suspension is known; it is the ratio of the density ($\rho$) of the suspension to the density of water (approximately 1000 kg/m³). 2. **Calculate the density of the suspension**: $ \rho = SG \times 1000 \text{ kg/m}^3 $ 3. **Calculate the total mass using density and volume**: Since density is the ratio of mass to volume, the total mass can also be calculated using density and volume: $ m = \rho \times V $ 4. **Distinguish between solid and liquid components**: - Assuming that the liquid component is mainly water, its mass is $m_{water} = \rho_{water} \times V$, where $\rho_{water} = 1000 \text{ kg/m}^3$. - The mass of the solid, $m_{solid}$, can be determined by subtracting the mass of water from the total mass: $ m_{solid} = m - m_{water} = (\rho - 1000) \times V $ In this way, it is possible to calculate the weight of the solid in the suspension based on its specific gravity and volume. Note that this calculation method assumes the density of the liquid phase to be constant (the density of water); in reality, it may vary due to dissolved substances or other factors. .