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Talk about this picture

2017-09-05View Original

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Talking about this diagram, 1. Is the DI circuit isolated by an optocoupler? With such a DI card, isn’t it unnecessary to use a relay for isolation? 2. How does the query voltage in the circuit work? 3. How do the capacitors and inductors in the circuit function? 4. Can this DO circuit output a passive signal?
Reply #22017-09-05
DI is opto-isolated; there is no need to measure voltage in the circuit. The capacitor is used to eliminate high-frequency interference signals. That is a resistor, not an inductor, and it serves to limit current flow. DO provides an output voltage of 48V/24V
Reply #32017-09-09
Thank you. There is one more question: the detection voltage in the DI circuit does not operate based on the principle of R=U/I. I wonder how it’s detected?
Reply #42017-09-09
Is the principle of DCS’s DI the same as that of PLC’s DI?
Reply #52017-09-09
After comparing, it seems the principle is the same. It’s the same except for the additional features.
Reply #62017-09-09
You might say that printed circuit boards are more or less similar, but if you look at them in detail, there are definitely differences
Reply #72017-09-10
This should be the schematic diagram of a DI module from some manufacturer. Understanding its principle allows for quick problem-solving at work.
Reply #82017-09-10
1.Is the DI circuit optocoupled? With such a DI card, isn’t it unnecessary to use a relay for isolation? Opto-isolation, that’s right. It is best to isolate the DI card with a relay. 4. Can this DO circuit output a passive signal? If the 24V supply at the contacts is not connected, the output will be passive; in the diagram, the output is 24V.
Reply #92018-01-03
MARK it, I’ll answer tomorrow

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