Issues with measuring gravitational pressure drop using differential pressure gauges
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A differential pressure transmitter is used to measure the pressure drop of a fluid before and after passing through a resistive element; there is a height difference at the fluid connection ports of the transmitter. If the fluid velocity is zero, is the reading displayed by the transmitter the static pressure difference before and after the resistance element (gravity-induced pressure drop)? Is it still zero?
Theoretically, it should be zero, but it is impossible for the high and low pressure tubes to have exactly the same height; therefore, there is a certain static pressure difference. The transmitter itself also has errors, and there are variations in the temperature of the liquid within the pressure tubes. As a result, it cannot be exactly zero, but as long as it remains within the allowable error range for measurement, it is considered acceptable.
How did the question end up in the title?
This is my first post; I’m not very good at it, please forgive me
Is it not possible to determine the gravitational loss of fluid from tube 2 to tube 1? Don’t understand the principle. The question is rather basic; please forgive me.
If you set a zero point before installation, the so-called \"gravity-induced pressure drop\" will not occur
I still don’t quite understand. Here’s the situation: I want to measure the flow loss as the fluid passes through a resistive element. Does the pressure drop measured by the differential pressure transmitter include only the frictional pressure drop and the form resistance pressure drop, without any need to account for gravity? .
If the medium being measured is a gas, there is basically no impact; if it is a liquid, it depends on the installation location of your transmitter.
When it comes to theory, then one must write down the measurement equations. Original poster, give Brother Pig my WeChat number 13709170262 and send a red envelope of 100 yuan. I’ll write equations for you that will benefit you for life, ensuring that nothing even the gods can defeat you. Is that okay? :P gaga gaga.
Bro Pig, are you referring to the Bernoulli equation and the energy equation?
No, it’s not. . . . . . Good morning, brother. The measurement equation I’m talking about is the mathematical equation that relates the reading of the differential pressure gauge, as shown in the diagram you drew, to the pressure difference across the two ends of the resistance element.