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For example, in the case of using a float to determine the level, the densities of the light medium and the heavy medium are 1100 KG/M3 and 1300 KG/M3 respectively. The float is 1 meter in length, and calibration is carried out by filling it with water. Since the densities of both the light and heavy media are greater than 1000, the water level must be above the float. If calibration is done by adjusting the zero point, such that 800 MM corresponds to 4 MA and 1000 MM corresponds to 20 MA, then how can the zero point be determined after calibration? If the approach of reducing the output is adopted, does that mean reducing the output within its range? Then how is zero determined? All the materials and posts I’ve seen before only covered the water-filling calibration method for float level gauges (when the density of the medium is greater than that of water) or interface gauges (when one of the media has a density greater than that of water and the other has a lower density). I’ve not encountered any methods for situations where both media have a density greater than that of water. Please discuss, thank you!
It’s just for discussion; it’s suspended using a spring scale
It seems that no one has encountered this issue; perhaps it’s simply impossible to verify it using the flooding method, and maybe no one knows about it either.
This post was last edited by 1111111 on 2019-8-15 at 11:51. Using heavy and light media for calibration is simple and accurate; then why use water for calibration? If you want to create a water school, you need to make two additional floats – want to know how to do that? :lol It’s a hassle to take such a detour; if you calculate things randomly, you can still achieve a similar result. The idea is too complicated – the waters of the Yellow River come from the heavens; my mind is in chaos........ :P August 15, 2019. Separator ---------------------------------------- Brother, I was just joking with you in March. You don’t need to make two extra floats; just use a brick to hit your head a hundred or so times, until it swells up. Once it’s swollen, you’ll be able to think more clearly. Why use water for that? If you still can’t figure it out, then use a sledgehammer or a heavy hammer to keep hitting your head, {:2_36:}
If it’s not a float, then a weight valve can’t be used, right? If it’s a float, then magnets should be used
If I don’t know how to use the water calibration method, I’ll just use the weight hanging method for calibration. At the lowest level, the buoy is submerged in the light medium; the corresponding weight to be applied is: buoy weight – buoyancy = buoy weight – buoy volume * density of the light medium. At the highest level, the buoy is submerged in the heavy medium, and the weight of the load is: buoy weight – buoyancy = buoy weight – buoy volume * density of the heavy medium. The weight and volume of the buoy are generally indicated on the nameplate.
Once calibrated with water, setting the scale range should work fine, right?
We’ve been discussing this for half a year now – have we reached any conclusions yet? ... The density of both liquid materials is greater than that of water, so what’s the difficulty in using water for calibration? ......They eat tofu; what’s so difficult about eating meat? Even eating swans involves using chopsticks to pick them up and teeth to chew them.... Ah, I really feel sorry for you...... Tell me, what kind of crappy school do you attend? What kind of terrible textbooks do you use? What kind of awful teachers do you have? How is it that even something as basic as using a float in water wasn’t taught to you properly? ........ It must be that you haven’t paid enough tuition! Or it’s your teacher who teaches you half-heartedly! {:2_33:} Defective items... :P ... Do you want to improve? Do you want to be fixed so they become good-quality items? If you really want to, knowledge and skills have their value. Come on, send an expensive WeChat red envelope to me so I can cover the tuition fees. 137 0917 0262. Guys, smile and line up to welcome the new students. {:2_36:} {:2_32:} {:2_40:} {:2_45:} {:2_42:} {:2_35:}
7th floor is correct. Calibration using the load-bearing method is a feasible and relatively accurate approach.
This post was last edited by 1111111 on 2019-8-15 at 14:42. It’s the “load-bearing method” – totally accurate. . . It’s fair to say it’s the least accurate. There’s no worse way to do it than this. The most accurate method is still to calibrate directly using a layered liquid mixture. Both the water calibration method and the weighing method are prone to introducing calculation errors and operational errors; the weighing method is even worse, being an outdated and inferior technique. . . .