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Process Engineering Section – Instrumentation and Automation Section – Daily Question – Question dated 2020-09-24: Discussion question: 245. Given that the length of the float is L = 800 mm, and the specific gravity of the liquid to be measured is r = 0.82 grams per square centimeter, use water for calibration. Calculate the heights of water filling required so that the output of the float level gauge is 20%, 40%, 80%, and 100%
When calibrated with water, the maximum height to which the float is submerged is given by: L_water = r_medium / r_water × L = (0.82/1) × 800 = 656 (mm). Dividing 656 mm into 10 equal parts, 10% of this value is 65.6 mm. Thus, the water levels corresponding to an output of 20%, 40%, 80%, and 100% from the float level gauge are 131.2 mm, 262.4 mm, 524.8 mm, and 656 mm respectively.
When calibrated with water, the maximum height to which the float is submerged is given by: L_water = r_medium / r_water × L = (0.82/1) × 800 = 656 (mm). Dividing 656 mm into 10 equal parts, 10% of this value is 65.6 mm. Thus, the water levels corresponding to an output of 20%, 40%, 80%, and 100% from the float level gauge are 131.2 mm, 262.4 mm, 524.8 mm, and 656 mm respectively.
131.2mm,262.4mm,524.8mm,656mm。
When calibrated with water, the maximum height to which the float is submerged is given by: L_water = r_medium / r_water × L = (0.82/1) × 800 = 656 (mm). Dividing 656 mm into 10 equal parts, 10% of this value is 65.6 mm. Thus, the water levels corresponding to an output of 20%, 40%, 80%, and 100% from the float level gauge are 131.2 mm, 262.4 mm, 524.8 mm, and 656 mm respectively.
When calibrated with water, the maximum height to which the float is submerged is given by: L_water = r_medium / r_water × L = (0.82/1) × 800 = 656 (mm). Dividing 656 mm into 10 equal parts, 10% of this value is 65.6 mm. Thus, the water levels corresponding to an output of 20%, 40%, 80%, and 100% from the float level gauge are 131.2 mm, 262.4 mm, 524.8 mm, and 656 mm respectively.
131.2mm,262.4mm,524.8mm,656mm。
131.2mm,262.4mm,524.8mm,656mm。
When calibrated with water, the maximum height to which the float is submerged is given by: L_water = r_medium / r_water × L = (0.82/1) × 800 = 656 (mm). Dividing 656 mm into 10 equal parts, 10% of this value is 65.6 mm. Thus, the water levels corresponding to an output of 20%, 40%, 80%, and 100% from the float level gauge are 131.2 mm, 262.4 mm, 524.8 mm, and 656 mm respectively.