Process Engineering Division – Instrumentation and Automation Section – Daily Topics – Topic No. 2020-12-19
Thread Content
Process Engineering Division – Instrumentation and Automation Section – Daily Topics – Topic No. 2020-12-19: Discussion question: 331. Given that the density of a certain fluid is 996 kg/m3 and its dynamic viscosity is 790×10-6 Pa·s, what is its kinematic viscosity? (5 points are given only to those who provide the correct answer; additional points are awarded for a correct calculation process or detailed explanation.)
Kinematic viscosity is the ratio of a fluid’s dynamic viscosity to its density ρ at the same temperature. ρ=η/ν=790×10-6Pas/996kg/m3×1000=793m2/s
0.793×10-6m2/s
Given that the density of a certain fluid is 996 kg/m3 and its dynamic viscosity is 790×10-6 Pa·s, what is its kinematic viscosity? Solution: Since the relationship between dynamic viscosity η and kinematic viscosity ν is η = ρ × ν, it follows that ν = η/ρ = 790×10-6/996 = 0.793×10-6 m2/s = 0.793 cSt. Answer: Its dynamic viscosity is 0.793 cSt (centistokes).
ν=η/ρ=790×10-6/996=0.793×10-6 m2/s=0.793 cSt.
ρ=η/ν=790×10-6Pas/996kg/m3×1000=793m2/s
Given that the density of a certain fluid is 996 kg/m3 and its dynamic viscosity is 790×10-6 Pa·s, what is its kinematic viscosity? Solution: Since the relationship between dynamic viscosity η and kinematic viscosity ν is η = ρ × ν, it follows that ν = η/ρ = 790×10-6/996 = 0.793×10-6 m2/s = 0.793 cSt. Answer: Its dynamic viscosity is 0.793 cSt (centistokes).
Kinematic viscosity is the ratio of a fluid’s dynamic viscosity to its density ρ at the same temperature. ρ=η/ν=790×10-6Pas/996kg/m3×1000=793m2/s
The relationship between dynamic viscosity η and kinematic viscosity ν is η=ρ×ν; therefore, ν=η/ρ=790×10-6/996=0.793×10-6 m2/s=0.793 cSt. Its dynamic viscosity is 0.793 cSt (centistokes).