How much oxygen is needed to produce 1000 cubic meters of water gas?
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The components of water gas are CO: 61%, H2: 32%, CO2: 5%, CH4: 1.5%, O2: 0.1%, and others: 0.4%. How much pure oxygen is required to produce water gas with these components? Given that the vapor-oxygen ratio is 0.84, can the oxygen demand be estimated? Everyone in the world of creating energy is part of one family; dear friends who are involved in creating energy, what is your experience level?
Is this a gas generator or a fixed-bed gasification system? You’re saying that it’s really impossible to calculate with these two numbers? Because according to material balance, attention also needs to be paid to the oxygen content in the raw coal and the flow rate of the raw coal
It is a fixed-bed gasifier. My rough calculations are as follows: 1. Oxygen input calculation – Oxygen required for gasification and combustion: 1500 Nm3/h ÷ 22.4 m3/kmol × 32 kg/kmol = 2142.86 kg/h. With an oxygen-to-vapor ratio of 0.83 kg/Nm3, the vapor flow rate is: 1400 Nm3/h × 0.83 kg/Nm3 = 1162 kg/h. Oxygen carried by the vapor: 1162 kg/h ÷ 18 kg/kmol × 16/18 = 918.12 kg/h. The oxygen content in coal, limestone, and the protective gas made up of carbon dioxide is ignored. The total is: 2142.86 kg/h + 1162 kg/h + 918.12 kg/h = 4222.98 kg/h. 2. Calculation of oxygen produced: The components of the gas generated by slag gasification are as follows: CO: 61%, CO2: 5%, H2: 31%, O2: 0.2%, and others: 2.8%. If the gas production rate is x Nm3/h, then: The oxygen content in CO in the gas is: 0.61x ÷ 22.4 m3/kmol × 16 kg/kmol = 0.436x. The oxygen content in CO2 in the gas is: 0.05x ÷ 22.4 m3/kmol × 32 kg/kmol = 0.071x. The oxygen content in O2 in the gas is: 0.002x ÷ 22.4 m3/kmol × 32 kg/kmol = 0.003x. The oxygen content in the solid materials carried out of the furnace, as well as that in the ash in the coal, is not taken into account. The total is: 0.436x + 0.071x + 0.003x = 0.51x. 3. Oxygen balance: Oxygen input to the furnace equals oxygen output, so: 0.51x = 4222.98 kg/h; therefore, x = 8280.35 Nm3/h