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What is the difference between hydrolysis and dissolution of paraformaldehyde? Does it release formaldehyde after dissolution, exist in the form of paraformaldehyde, or both?
1. Personal understanding of the essential difference between dissolution and hydrolysis comes from the understanding of these two words. Formaldehyde will be released slowly in water. Generally, in acid, formaldehyde will be released quickly under heating conditions. Depolymerization will also release formaldehyde slowly. The process is very slow. Heating is required and acidic conditions will accelerate the molecular formula (CH2O)n. Appearance and properties Low molecular weight is a white crystalline powder with a formaldehyde smell. Molecular weight (30)n Vapor pressure 0.19kPa/25℃ Flash point: 70℃ Melting point 120~170℃ Solubility Insoluble in ethanol, slightly soluble in cold water, soluble in dilute acid and dilute alkali Density Relative density (water = 1) 1.39 ; Relative density (air=1)1.03 Stability is stable
Hydrolysis and dissolution are different. Hydrolysis is the reaction with water to generate other substances, which is a chemical change, while dissolution is a physical change. The hydrolysis process is generally accompanied by dissolution, but the dissolution process does not necessarily include hydrolysis. Personal opinion!
hydrolysis: A reaction between a substance and water that results in the decomposition of water. Such as the hydrolysis of salts composed of weak acid radicals or weak base ions. Dissolve: The process by which one substance (solute) is dispersed in another substance (solvent) to form a solution. For example, salt or sucrose is dissolved in water to form an aqueous solution.
Sorry, the way I asked the question misled everyone. The main question I want to ask is, during the dissolution process of paraformaldehyde, will its macromolecules depolymerize into small molecules? In what form does formaldehyde exist in solution? This post was last edited by Arctic Circle on 2009-3-19 16:35 ]
Mainly in the form of hemiacetal in solvents.
Thank you Cangban for your enthusiastic answer, learn from* .