Calculation of the effective power of centrifugal pumps
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The effective power of the pump is HQg; why isn’t pressure taken into account? If the outlet pressure is not at atmospheric level, how should the effective power be calculated?
This post was last edited by ylb913 on 2017-2-5 at 11:02. You missed in including the density ρ; H represents the head, and the pressure is obtained by multiplying H by ρ and g. P=ρgH
Oh, I see. Thank you!
That’s not right; if a pump is used to transfer water from tank 1 to tank 2, the effective power of the pump remains the same regardless of whether the pressure in tank 2 is 1 MPa or 2 MPa
H is different; H needs to be calculated using Bernoulli’s equation, and frictional forces also need to be taken into account
It’s not clear what exactly needs to be calculated
Power = density * gravitational acceleration * flow rate * head; there are certain techniques involved in identifying and calculating the head