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The pump manufacturer provided a maximum flow rate of 271 cubic meters per hour. This pump is used to pump methanol and water, and I would like to know what the corresponding maximum flow rate would be in tons per hour
【The data provided by the manufacturer indicates that the maximum flow rate is 271 cubic meters per hour】, with water as the medium and a temperature of 20 degrees. The flow rate can be calculated using the density and temperature of methanol and water. The flow rate is denoted by Q, with units of cubic meters per hour (m3/h), liters per second (l/s); 1 l/s = 3.6 m3/h = 0.06 m3/min = 60 l/min. The formula is G = Qρ, where G represents weight and ρ represents the specific gravity of the liquid
Thank you for your comment. Can we assume that the volume of different objects is fixed? Is it to convert it into density?
Buy a methanol-water density meter. . . It’s very cheap. . . Additionally, if you know the ratio between the two, search online for a table of methanol-water densities. . .
For density ratio, water has a value of exactly 1; by multiplying this by the density of the actual medium, a direct reading can be obtained.
Just multiply by the specific gravity of the medium; 271 cubic meters, with a specific gravity of 0.79 for methanol, results in 214 tons per hour. For water, it’s 271 tons per hour
The actual flow rate of the pump can be found in the data sheet provided by the manufacturer; it is necessary to use a flow meter for measurement. The scale of the flow meter needs to be adjusted according to the medium used (the adjustment method varies depending on the type of flow meter)
Can it be assumed that what the manufacturer provides is the volumetric flow rate – that is, the same volume regardless of the material being handled? To calculate the weight in tons, one simply multiplies this value by the specific gravity, right? Thank you for your answer