HCBBS Forum (English)
Submit Chemical Projects / Find Solutions
Amplify Your Requirements on a Broader Chemical Platform *Engineering · Technology · Equipment · Solutions*
Submit Request

【Haichuan Teahouse】Brain-teasing Series: Said to be a turning point

2021-07-15View Original

Thread Content

Question: The side length of square ABCD is 12, and the radius of the incircle of triangle EDC is 3. Find the area of the shaded region.
Reply #22021-07-15
How was it calculated? Was it done using CAD drawing methods again? ? Middle school students don’t know CAD
Reply #32021-07-16
Calculating the area of the triangle: By connecting the incenter O to the 3 vertices, the two legs have lengths 3+9 and 3+X, while the hypotenuse has length 9+x (using the method of the inscribed circle and the angle-bisector theorem). Applying the Pythagorean theorem yields x=6; the area of the triangle is therefore 54, and 144–54=90
Reply #42021-07-16
Mainly, I can’t recall the properties of the incircle of a triangle, so I couldn’t derive that the hypotenuse equals 9+x. If it is known that the angle between a side and the center of the circle is a right angle, then using the property of congruent triangles, it can be determined that the hypotenuse equals 9+x; thus, X=6:victory:

Submit a Project

**Looking for Chemical Technology, Equipment & Solutions?** No Registration Required Broader Platform Exposure | Global Chemical Service Provider Connections

Submit Request — Free Consultation

Disclaimer

This is an automated machine translation of the original thread. Some technical terms may have inaccuracies; the original text shall prevail. Click "View Original" at the top right to access the source page, which supports IP-based automatic real-time language translation. Please watch out for contact details and sales inducements to prevent fraud. All content and translations are for reference only, representing solely the poster's personal views. For enquiries, email service@hcbbs.com.