The issue of nitrogen flushing for containers
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I have a question for everyone: For a container with a volume of 1000 m3, how much pressure can be achieved by filling it with nitrogen to 0.4 MPa? How many m3 are required to fill to the target pressure using nitrogen at each of the following pressures? 1. Low-pressure nitrogen: 0.4 MPa 2. Medium-pressure nitrogen: 2.5 MPa 3. High-pressure nitrogen: 15.0 MPa. How can this be estimated roughly? I have a rough idea of how to estimate it; I’m hoping someone experienced can help calculate it and tell me if my estimate is correct.
This post was last edited by ylb913 on 2015-6-16 at 11:28. It is difficult to estimate the amount of gas that needs to be removed from the storage tank; if removal isn’t necessary: for a container with a volume of 1000 m3, nitrogen is used to push the pressure up to 0.4 MPa (gauge pressure), while the initial pressure inside the container is 0.1 MPa (absolute pressure), so an additional 0.4 MPa of pressure needs to be applied. Assuming the temperature is constant, using P1V1=P2V2: P2V2=0.4*1000=400. 1. Using low-pressure nitrogen at 0.4 MPa, with a gauge pressure of 0.5 MPa, V1=400/0.5=800 m3 ； 2. Use medium-pressure nitrogen at 2.5 MPa; V1 = 400/2.6 = 154 m3 ； 3. Use high-pressure nitrogen at 15.0 MPa, V1=400/15.1=26.5 m3
I’m truly impressed by the solid theoretical foundation; the law of conservation of energy should be applied here!
How is calculated the time it takes for the technician to reach the required pressure? Also, can you calculate the flow rate and residence time of oil in the pipeline? I would like to ask the teacher. Thank you
Actually, it doesn’t matter how long it takes to reach the desired pressure; what we use most is to report for scheduling how much nitrogen is needed: lol