Dyne calculation method

I’m not quite sure what the question is; 1 Newton = 100,000 dynes

There is still 4 kilodynes of work remaining, as stated by the engineering department. I’m not sure how this amount is calculated – is it related to the wall thickness of the pipes?

Found online: Calculation method for “dyne” in pipeline construction: A dyne is a unit used to calculate the amount of work required for welding. Generally, one ring weld on an inch-long pipe is considered one dyne; however, depending on the wall thickness of the pipe and the type of weld, the following weighted calculation formula is used: Dyne value = K × nominal diameter of the pipe (in inches). Note: The value of K is determined as follows: 1. For butt welds, if δ < 8 mm, then K = 1; if 8 mm ≤ δ < 12 mm, then K = 1.2; if 12 mm ≤ δ < 16 mm, then K = 1.3; if 16 mm ≤ δ < 19 mm, then K = 1.5; if 19 mm ≤ δ < 23 mm, then K = 2; if 23 mm ≤ δ < 27 mm, then K = 3; if 27 mm ≤ δ < 31 mm, then K = 4; if 31 mm ≤ δ < 35 mm, then K = 5; if 35 mm ≤ δ < 39 mm, then K = 6. 2. For general socket welds, the dyne value is calculated as 0.7 times that of butt welds with the same diameter and wall thickness； 3. For tees without reinforcement plates, the value is calculated as 1 time the size of the butt weld with the same pipe diameter and wall thickness as the branch pipe ； 4. For tees with reinforcement plates, in addition to the calculation according to item 3, an additional factor of 0.5 is applied, which is calculated based on the inner and outer diameters and wall thickness of the reinforcement plates ； 5. The weld seam of the thick tube boss shall be calculated as 3 times that of a butt weld seam with the same diameter and wall thickness as the boss ； 6. Ordinary bosses are calculated as 1 time the butt weld size for the same pipe diameter and wall thickness.

Haven’t dealt with this kind of issue before; now I’ve experienced it

I was wondering if this algorithm has any source or basis? ? ?