Here we go again, a question on physical chemistry; let’s discuss it together
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According to Clapeyron’s equation, what must happen to the melting point of ice when pressure increases? After reading the book, I feel like I don’t fully understand it!
Personally, I think the melting point will decrease; it’s easy to understand if you think about how ice forms on the heels of shoes after walking in snow in winter
Well, I also feel that it will decrease, but according to that formula, I don’t understand it
The Clapeyron equation dP/dT=ΔH/(TΔV) applies to the melting of ice into water; here ΔV is negative, so dP/dT is negative. When dP is positive, dT is negative, meaning the temperature decreases
The original poster is right! That’s how it should be analyzed!