May I ask, when saturated steam at 0.4 MPA (gauge pressure) is reduced to 0.05 MPA, by how many degrees does the temperature of the steam increase?
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When saturated steam at 0.4 MPA (gauge pressure) is reduced to 0.05 MPA (gauge pressure), turning it into superheated steam at 0.05 MPA, by how many degrees does its temperature increase compared to that of saturated steam at 0.05 MPA? How is it calculated? ?
As the compression temperature increases, does the decompression temperature decrease?
It depends on the way you reduce pressure; for example, a pressure relief valve involves an isenthalpic process. At 0.4 MPa, the enthalpy of saturated steam (151.9°C) is 2748.7 KJ/KG; therefore, by referring to the steam table, the temperature at the same enthalpy at 0.05 MPa is 138.3°C. At 0.05 MPa, the temperature of saturated steam is 111.37°C; at this point it is superheated steam.
After decompression, the pressure decreases while the temperature remains constant; it is superheated steam. The corresponding temperature for saturated steam at 0.4 MPa (gauge pressure) can be looked up. My personal understanding.........