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As the pressure at the top of the stabilizer increases, how does the temperature at the top change?

2015-10-22View Original

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This post was last edited by hao0080 on 2015-10-22 at 20:19. I’m just starting to learn about catalytic cracking; today we discussed the issue of stabilizer pressure, and it was mentioned that \"when the pressure at the top of the stabilizer increases, how does the temperature at the top change, assuming all other conditions remain constant?\" ”I hope the experts here can help me solve this problem.
Reply #22015-10-22
“As the pressure at the top of the stabilizer increases, the temperature at the top rises, assuming all other conditions remain unchanged.
Reply #32015-10-22
Thank you. I was wondering if there are any explanations based on principles or practical experience to share? What we’re discussing today is the decrease in top temperature... so it’s confusing... I later ran a simulation, and when the pressure was increased, the trend of the top temperature was to first decrease and then increase.
Reply #42015-10-22
You can take a look at how many posts He Guangtao (24123) has made today.
Reply #52015-10-22
Thank you, but what I would like to ask is about the catalytic cracking unit.
Reply #62015-10-26
With all other conditions unchanged, will the pressure increase on its own? I think you should consider the reasons for the increased pressure in order to decide on the appropriate top temperature. For example, if the reflux rate is high, the pressure rises and the top temperature drops; if the load is high, the pressure increases, and the overall temperature of the tower rises as well, which in turn causes the top temperature to increase. There are always reasons behind these changes – one factor affects everything else, so it’s not possible to consider things in isolation. (Personal opinion)
Reply #72015-10-26
In daily life, pressure cookers are a great example
Reply #82015-10-26
Temperature and pressure are synchronized; the main reason for the increase in pressure is the rise in temperature
Reply #92015-10-27
It’s thermal expansion and contraction; it’s more or less the same. I think thinking in that way is acceptable

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