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Regarding the issue of switching to a different pump

2015-11-13View Original

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This post was last edited by *nht1 on 2015-11-16 at 13:11. A pump has a flow rate of 10 m3, a head of 35 m; the density of the liquid being transported is currently 1.05, and its power consumption is 3 KW. Is it possible to use this pump to transport a saline solution with a density of 1.25? If pipes of size 108*4 are used for a transmission distance of 200 m, what will be the maximum flow rate?
Reply #22015-11-13
It’s not a problem with the pump; it’s a matter of the size of the motor used with it.
Reply #32015-11-13
The analysis is quite thorough; it is now necessary to determine whether the motor can still meet the requirements
Reply #42015-11-16
Talk to the pump manufacturer and check the pump’s performance curve.
Reply #52015-11-16
As a supplementary note, is this the formula for calculating shaft power? The shaft power P = ρgQH/1000η (in kw). Could the expert explain again the origin of this formula and its specific meaning?
Reply #62015-11-16
Personally, I think there is a problem with this formula; the 1000 at the bottom should be 3600, which is used for unit conversion! The pump shaft power P = {head * flow rate (m3/s) * medium density * gravitational acceleration} / pump efficiency. This is essentially a process of energy conversion; the amount of work required to lift the slurry to a certain height is determined by these factors... I seek guidance from experts...

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