20151119 Daily Question
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The rewards for the daily question on 20151119 are as follows: 1–3 points for active participation, 5 points for correct answers, and 8–10 points for correct answers accompanied by an analysis. Regarding the calculated load for 3 or 2 electrical devices, ( ). A. Take the sum of the powers of all devices. B. Take the sum of the powers of all devices and multiply it by a coefficient of 0.8. C. Take the sum of the powers of all devices and multiply it by a coefficient of 0.85. D. Take the sum of the powers of all devices and multiply it by a coefficient of 0.99. The answer is A
A. Add up the power of each device.
For the calculated load of 3 or 2 electrical equipment units, (A ).
For the calculated load of 3 or 2 electrical devices, (A. Take the sum of the power of each device).
For the calculated load of 3 or 2 electrical equipment units, (A).
Answer: A (the sum of the powers of each device). Section (4) of Chapter 1 in the third edition of the \"Manual for Industrial and Civil Power Distribution Design\" states that for a small number of electrical devices (4 or fewer), the calculated load for 3 devices or 2 devices is equal to the sum of the powers of each device； The calculated load for 4 electrical devices is obtained by multiplying the sum of the device powers by a coefficient of 0.9.
For the calculated load of 3 or 2 electrical equipment units, (A). A. Take the sum of the powers of all devices. B. Take the sum of the powers of all devices and multiply it by a coefficient of 0.8. C. Take the sum of the powers of all devices and multiply it by a coefficient of 0.85. D. Take the sum of the powers of all devices and multiply it by a coefficient of 0.99
For the calculated load of 3 and 2 electrical equipment units, (a). A. Take the sum of the powers of each device