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★Specialized Examination for Chemical Engineering ★ — One question per day (2015-11-30) — Points are awarded for participation

2015-11-30View Original

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This post was last edited by zshiwei2008 on 2015-12-1 09:30. Points system for the daily question: Participation – 1~3 points; Correct answer – 5 points; In-depth analysis – 5~10 points. The answer is provided the next day. Due to limited capabilities, I am unable to provide more in-depth explanations for each question; therefore, on the second day, in addition to offering reference options, I will also remove the restriction on reading replies. I hope that all candidates can learn from one another and improve together! Daily Question (2015-11-30): 1. Divide a container into two equal parts using a partition; put CO2 in one part and H2 in the other. If the masses of the gases on both sides are equal and their temperatures are also equal, then, assuming no friction between the partition and the vessel walls, what happens to the partition? A. Will not move B. Move towards the side containing CO2 gas C. Move towards the side containing H2 D. Cannot be determined 2. For a liquid-liquid phase equilibrium system, the phase equilibrium criterion that must be satisfied by each component is ( ). A. The fugacities of each component in the two phases are equal, and the activity coefficients are also equal. B. The fugacities of each component in the two phases are equal, and the activities are also equal. C. The fugacity coefficients of each component in the two phases are equal, and the activity coefficients are also equal. D. The fugacity coefficients of each component in the two phases are equal, and the chemical potentials are also equal. Answer keys: 1, B; 2, B
Reply #22015-11-30
1、B; With equal mass, the amount of substance of hydrogen is greater than that of carbon dioxide; at equilibrium (with the same temperature), the volume of hydrogen will be 22 times that of carbon dioxide. 2、D
Reply #32015-11-30
This post was last edited by Anran on 2015-11-30 09:57. 1. Choice: B. Move towards the side containing CO2 gas. 2. Choice: B. The fugacities of each component are equal in both phases, and their activities are also equal
Reply #42015-11-30
1. B. Move toward the side containing CO2 gas. According to the gas law PV = mRT/M, when m, T, and V are constant, the pressure of a gas with a lower molar mass M is greater than that of a gas with a higher molar mass M. Therefore, in the container shown in the diagram, the molar mass of hydrogen is smaller than that of carbon dioxide; as a result, the pressure of hydrogen is greater than that of carbon dioxide, and the partition will move toward the side containing carbon dioxide. 2. B. The fugacities of each component in the two phases are equal, and their activities are also equal

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