I would like to ask if there is any issue with the square root function in differential pressure transmitters

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There is a pneumatic differential pressure transmitter with a measurement range of 2500 Pa; the corresponding maximum flow rate is 50 t/h. The process requirement is that an alarm be triggered at a flow rate of 40 t/h. Question: (1) What is the transmitter differential pressure without a square rooter? (2) What is the transmitter differential pressure with a square rooter? Solution: 1. Without a square root function, the differential pressure corresponding to a flow rate of 40 t/h is ΔP1 = 2500 × (40/50)² = 1600 Pa. 2. With a square root function, since ΔQ = K × ΔP, the differential pressure for a flow rate of 40 t/h is ΔP2 = 2500 × (40/50) = 2000 Pa. My understanding is that without the square root function, ΔP1 = 2500 × (40/50) = 2000 Pa; while with it, ΔP2 = 2500 × (40/50)² = 1600 Pa. Could someone please tell me which answer is correct?