Heat recovery calculation
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Hello, experts at HaiChuan: The temperature of the concentrate after fermentation is approximately 70°C, with a volume of 20 T. I want to use its heat to cool water to 35°C in one go. I would like to ask how much heat can be recycled? How much 0.6MP of steam has been saved as a result? Thank you
It’s approximately 700,000 kilocalories of heat, which equates to a savings of around 1,400 KG of steam at 0.6 MPA pressure.
Could you explain how to calculate this?
How is it calculated? What should be used as the specific heat of the concentrate?
Firstly, hot water with a temperature below 70 degrees has a very low quality; in my opinion, it is generally not considered suitable for recycling – I’m not sure what purpose it could serve Secondly, it is necessary to know the purpose in order to determine the heat utilization rate and calculate how much low-pressure steam is equivalent to it.
Q=20T/H*CP*(70-35)=M(water)*CP(water)*temperature difference. Since the information you provided is insufficient, this is the best way to explain it to you