If the temperature of saturated water vapor remains constant while the pressure decreases, is it a subcooler or a superheater?
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The temperature remains constant while the volume increases (depression in pressure), which indicates a unsaturated state; yet according to the phase transition diagram it is considered superheated. How can there be two different conclusions? I seek guidance from experts to resolve this confusion
Superheated steam is not saturated steam itself. Using the term “unsaturated” is a bit awkward.
By looking at the pressure-enthalpy diagram of water, it can be seen that the conditions before and after the inflection point on the saturated steam line are different.
Is saturated steam, when the temperature remains constant but the volume increases (pressure decreases), subcooled and unsaturated?
The key is to keep the temperature constant! ! If the temperature remains constant while the pressure decreases, what could it be other than superheating?
Unsaturated steam is simply superheated steam; it’s the same thing
If the temperature remains constant and the volume is increased, then the pressure will drop, resulting in unsaturation, right?
There are two types of unsaturation: superheated unsaturation and non-superheated unsaturation