The difference between water pumps and oil pumps

Centrifugal pumps generally rotate at 2,900 revolutions per minute, with high speeds of rotation; volume pumps have lower rotation speeds, and their flow rate and head can be estimated based on the rotation speed. When transporting viscous substances, the higher the viscosity, the lower the rotation speed should be. It’s like walking in a mud puddle; if you try to walk faster, you just get more tired. The speed of movement isn’t much faster; it doesn’t advance step by step slowly.

Hello, all my discussions are within the scope of centrifugal pumps. Because oil with a higher viscosity cannot be pumped, according to the pump manufacturers. In my opinion, as long as the motor is made larger, why shouldn’t it be possible to pump it?

The head of a pump is determined by the impeller curve of the pump, and it has nothing to do with the size of the motor. You just need to meet the shaft power requirement. It’s a waste no matter how large the motor you replace is. Oils with high viscosity exhibit strong adhesive forces during centrifugation, resulting in very low mechanical efficiency. You can choose a positive displacement pump, such as a screw pump

Centrifugal pumps transport liquids by means of centrifugal force, that is, inertia, which pushes the liquid outward. They work well with liquids that have a low specific gravity; however, when the liquid’s specific gravity increases and its viscosity rises, it may stick to the impeller and thus not be pushed outward. I’m not sure if what I’m saying is correct; this is just my personal understanding, so please don’t take it personally

Let’s take a look at Guan Xingfan’s books, shall we? . . Why can’t it be oiled? . . Oils with a viscosity high to a certain degree cannot be pumped using centrifugal pumps, as their performance will decline. . I remember that pumps with a viscosity below 1000 cSt can be used with centrifugal pumps. However, the general rule applies to values below 150 cSt. . I can’t remember exactly, but it’s probably this value. . Develop a proper sealing flushing plan as well as carry out viscosity conversion. . For low flow rates, the high-viscosity medium is represented by a table. . For high flow rates, there is another table for high-viscosity media. . . Do your own research. . Ultimately, isn’t this thing just like that? . The baby feels sad; the baby won’t tell you about the changes in pump performance when transporting special liquids, as described on page 168, section 6.14 of Guan Wei Fan’s Modern Pump Theory and Design. . . There are conversion tables with examples. .

What does it matter if the shaft power is high but the mechanical efficiency is low?

If the motor is larger and the power on the input shaft is greater, doesn’t that mean there’s more force?

I remember that generally, higher viscosity oils require higher temperatures for transportation. . So oil pumps are generally supported by a centerline. . Don’t pay attention to that cantilevered part of yours. Anyway, grasp something. . Pump manufacturers, seeing that you’re an outsider, like to play around with concepts when dealing with you. . I just love tricking customers like this. . Anyway, they don’t understand. . Why use a centerline support instead of footings? . This is mainly due to the different coefficients of linear expansion among the pump body, impeller, and shaft. . If it’s supported at the base, an increase in temperature can easily cause wear on the sealing ring, leading to problems with noise, vibration, and the mechanical seal as well. . That’s why the manufacturer tells you that the oil pump should be designed as a cantilever type. . . It’s two points. . One is to use it as a centerline support. . . The second is bearing housing heat dissipation. . Water cooling is usually used. . In western regions where such conditions are not available, heat-resistant oils or greases should be used, along with air cooling. That’s all there is to it. . The baby feels sad inside. . The baby doesn’t even want to tell you guys. . These are all the baby’s experiences. .

Once you’ve spent 100 units of electricity but only achieved 1 unit of useful work, while someone else can use 100 units of electricity to produce 70 units of useful work, you won’t think this way anymore.

Wrong. . Can it be calculated this way? . . Think about the torque formula by yourself. . Let me think about it. . When the impeller size and rotational speed are the same. . . I used a regular IH50-32-125 pump running at 2900 revolutions per minute. . . I have one paired with 2.2KW-2. . It is equipped with a 15KW-2 motor. . . I’m using the same medium. . And both the flow rate and head are 12.5 cubic meters. . 20 meters. . . Try calculating the current yourself using a clamp meter. . In reality, the output power of the two motors should be approximately the same. .