Material balance of the ammonia vaporization tower
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The flow rate of ammonia water remaining in the tower is 33 cubic meters per hour, and it is heated with direct steam. So, how much ammonia-containing wastewater and concentrated ammonia water with a concentration of 10–12% is generated per hour?
For the remaining ammonia water, the amount of ammonia is taken as 5 g, and that of steam as 150. For concentrated ammonia water: 5*1000*33/0.1/1000000 = 1.65 t/h. The amount of ammonia-containing wastewater generated is 33*1.15 – 1.65 = 36.3 t/h
Without considering ammonia in the wastewater
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Could you explain the calculation process? I didn’t understand it. Thank you
5g/L * 1000L = 5 Kg/m3. 5 Kg/m3 * 33 m3/h = 165 Kg/h (ammonia content). 165 Kg / 10% = 1650 Kg/h = 1.65 tons/h. 150 Kg of steam is required per ton of water, so the total amount per hour is 33 * 1.15. Then, by subtracting the concentrated ammonia vaporized, what remains is the amount of wastewater
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