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During the reaction of the product, inorganic salts and trace amounts of organic salts are formed. Theoretically, these inorganic salts should dissolve in the water present in other materials within the process, but this does not happen in practice; the water in the mother liquor remains unsaturated, and the inorganic salts cannot dissolve in it. Therefore, more water has to be added. I would appreciate it if someone could explain this phenomenon. Is there anything such as an inorganic salt solubilizer? For example? Thank you!
The solubility of inorganic salts in water is related to temperature and pH; considering adjustments to temperature and pH might be advisable. As for the use of inorganic salt solubilizers (it’s not clear whether such substances exist), it would introduce other impurities.
By inorganic salts, I mean sodium chloride; its solubility in water is hardly affected by temperature, and whether it is influenced by pH has not been studied
{:3_46:} When the chloride ion concentration is high, the solubility of sodium chloride decreases; as the polarity of the aqueous solution decreases, its solubility also drops. For example, when certain organic acids are dissolved in water, the salt will not be saturated. By controlling the temperature and reducing the mutual solubility between the material and water, it is possible to increase the solubility of the salt
The solution corresponding to inorganic salts should be an aqueous solution in which other substances are dissolved; the solubility cannot be referred to in terms of water