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Help needed

2016-06-14View Original

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For a pipeline with a volume of 5000 cubic meters, which is already filled with nitrogen at a pressure of 1.6 Mpa, and the pressure is to be increased to 2.5 Mpa, how many cubic meters of nitrogen are required? I would appreciate it if someone could explain how to calculate this
Reply #22016-06-14
Can the ideal gas law pv=nRT be used?
Reply #32016-06-14
5000*(25-16)=45000m3
Reply #42016-06-14
The amount of nitrogen that can be stored in a 5000 m³ pipeline at a pressure of 2.5 MPA, minus the amount of nitrogen stored at a pressure of 1.6 MPA, equals the amount of nitrogen that needs to be replenished. You haven’t provided the pipe temperature; it is currently assumed to be 0 degrees. If the temperature was 20 degrees at that time, the gas consumption would be lower, by about 20/293.
Reply #52016-06-15
Could you tell me which formula is being used? Thank you
Reply #62016-06-15
P mark V mark/T mark = PV/T; temperature is in K scale
Reply #72016-06-15
For gases, PV=nRT; the ideal gas equation can be used at low pressures. Low pressure

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