Insulation layer calculation – I need expert advice. Why does it always seem like there’s a decimal point missing? ! !
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file:///D:\Documents\Tencent Files\437561288\Image\Group\)3HCGDDT~KC81~UJAXLKXWK.pngfile:///D:\Documents\Tencent Files\437561288\Image\Group\`U@EH4NLGBV@7N7I_MC6XE.jpgI’m hoping experts can help me understand why it always seems like there’s a missing decimal point ? ? Where is the difference in units?
δ2=λ/αs(to-ts)/(ts-t0) – Formula for calculating heat insulation to prevent burns; double-layer insulation; aluminum silicate; 565–300. δ1 = 0.013071375; insulation thickness in meters. λ1 = 0.1285; thermal conductivity of the insulation material in W/(m*℃). αs = 8.141; heat loss coefficient from the outer surface of the insulation layer in W/(m2*℃). to = 565; external surface temperature of the equipment in ℃. ta = -20; ambient temperature in ℃. ts = 300; external surface temperature of the insulation layer in ℃. Rock wool: 300–60. δ2 = 0.025205749; insulation thickness in meters. λ2 = 0.0684; thermal conductivity of the insulation material in W/(m*℃). αs = 8.141; heat loss coefficient from the outer surface of the insulation layer in W/(m2*℃). to = 300; external surface temperature of the equipment in ℃. ta = -20; ambient temperature in ℃. ts = 60; external surface temperature of the insulation layer in ℃. 0.042, 0.0002; 565, 300; 0.1285, λ1 = 0.036, 0.00018; 300, 60; 0.0684, λ2