Calculate evaporation amount
Thread Content
Diethyl sulfate has a boiling point of 209 degrees. I heat it to 90 degrees; I know its saturated vapor pressure. So how can I calculate the amount of evaporation that occurs after heating? It’s in a tank with a capacity of 2000 liters
It’s precisely because I don’t know that I want to calculate it~~ The vapor pressure at this temperature is 2 KPa, which is very low; does that mean there’s basically no vapor? Is it related to the amount of solvent?
This amount can’t really be considered evaporation; it should rather be called volatilization~:lol
Does that mean the volatilization rate is very low? If I heat 1000 liters of this solvent, how do I calculate its volatilization rate?
Calculate it based on mass transfer principles; the driving force is naturally the concentration difference between the liquid surface and the gas phase. Then, find the gas-phase mass transfer coefficient for that substance (to be honest, I’m not sure whether it’s possible to find such a value). Estimate the mass transfer rate, and then multiply that rate by time to obtain the quantity involved. In theory, this is how the amount of volatilization is calculated – well, at least in theory. . . .
The evaporation rate is too low; a rough estimate shows that it’s less than 1 gram per second. Even when heated at 90 degrees for an hour, only one or two kilograms will evaporate.
How do you calculate this? What’s the formula?
The simplest algorithm is to use the saturated vapor pressure for estimation. You know the boiler pressure and the saturated vapor pressure of the medium; don’t you know how to calculate the volume fraction of the medium in the gas? Knowing the volume fraction and the volume of the gas phase space in the reactor, can it be determined soon how much has evaporated?
I don’t know the pressure in the kettle~ It’s at atmospheric pressure before heating, and I still don’t know what the pressure will be after heating