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The medium is LNG (gas), with a flow rate of Q1=14000 Nm3/h and an inlet pressure of 250 mbar. What is the actual operating flow rate of LNG at -140 degrees Celsius? How is this calculated? Can we simply use V1*P1/T1=V2*P2/T2? V1=14000, P1=100kpa (1 atmosphere), T1=273K (0 degrees Celsius). P2=25kpa, T2=172K (-140 degrees Celsius). I calculated using the above formulas; the values and units are as listed. However, the value of V2 obtained as a result is extremely high, which is clearly unreasonable. Could someone please help me understand this? @lushiru @yaoshuyan @Liu Jiajia @Mr. Zhang 2015 @Benbang Self-Regulating Valve – Engineer Li @dearyuer @Yunmu @955559
Calculate using density: 14,000*0.828 = 11.6 tons/h as the LNG volume flow rate; 11.6/0.44 = 26.3 cubic meters/h
Are 0.828 and 0.44 the densities of LNG at standard conditions and at -140 degrees Celsius, respectively? Where can I find this value? Thank you.
The density of the gas should be 0.828 kg/m3, while its density in the liquid state under operating conditions is 0.44 T/m3. Thank you. Where can I find this density? Boss.
Does this have nothing to do with the inlet pressure?
-At 140 degrees, LNG is in a liquid state; its volume is approximately 1/600 of the volume it would have in gaseous form, and it cannot be simply calculated using gas-state equations
I also think it’s unreasonable to use the gas equation of state; then, is the calculation on the second floor acceptable? Thank you, hero!
Using density is a reasonable approach; it is necessary to check the density of LNG under those operating conditions as well as the density of the gas at standard conditions.
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